RE: Error in the EVAL Statement? (when + is used more than once)

I did the following:

D amount1         S             25S 0 inz(2)
D amount2         S             25S 0
C                   EVAL      amount2 = amount1 ++ 10
C                   EVAL      amount2 = amount1 +- 10
C***                EVAL      amount2 = amount1 +* 10
C***                EVAL      amount2 = amount1 +/ 10
C                   EVAL      amount2 = amount1 -+ 10
C                   EVAL      amount2 = amount1 -- 10
C***                EVAL      amount2 = amount1 -* 10
C***                EVAL      amount2 = amount1 -/ 10
C                   EVAL      amount2 = amount1 *+ 10
C                   EVAL      amount2 = amount1 *- 10
C                   EVAL      amount2 = amount1 ** 10
C***                EVAL      amount2 = amount1 */ 10
C                   EVAL      amount2 = amount1 /+ 10
C                   EVAL      amount2 = amount1 /- 10
C***                EVAL      amount2 = amount1 /* 10
C***                EVAL      amount2 = amount1 // 10

The results were as follows (commented out lines were invalid).

12
-8
-8
12
20
-20
1024
0
0

> -----Original Message-----
> From: Peter_Vidal@pall.com [SMTP:Peter_Vidal@pall.com]
> Sent: Friday, August 02, 2002 03:12 PM
> To:   rpg400-l@midrange.com
> Subject:      RE: Error in the EVAL Statement? (when + is used more than once)
>
>
> "I think it's taking the second + as a sign."
>
> That may be the reason Jim.  I also tried the * and it is a error. I think 
>this
> clarifies my doubt on this matter.
> However, I tried this now:
>
> c                   z-add     502.34        amount1           7 2
> c                   z-add     0             amount2           7 2
>
> c                   eval      amount2 = amount1 + + 7
> c                             500.00
>
> c                   seton
>
> You know the result? 8002.34
>
> How?
> Peter Vidal
> PALL Aeropower Corp.
> Senior Programmer Analyst
>
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