RE: Error in the EVAL Statement? (when + is used more than once)

[rob@xxxxxxxxx]

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I think we would have seen a better sample on the
/+
/-

If you had not defined those fields with zero decimal places  :-)

Rob Berendt
--
"They that can give up essential liberty to obtain a little temporary
safety deserve neither liberty nor safety."
Benjamin Franklin




"Ray, Adam" <ARay@wipfli.com>
Sent by: rpg400-l-admin@midrange.com
08/02/2002 03:33 PM
Please respond to rpg400-l


        To:     <rpg400-l@midrange.com>
        cc:
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        Subject:        RE: Error in the EVAL Statement? (when + is used more 
than once)


I did the following:

D amount1         S             25S 0 inz(2)
D amount2         S             25S 0
C                   EVAL      amount2 = amount1 ++ 10
C                   EVAL      amount2 = amount1 +- 10
C***                EVAL      amount2 = amount1 +* 10
C***                EVAL      amount2 = amount1 +/ 10
C                   EVAL      amount2 = amount1 -+ 10
C                   EVAL      amount2 = amount1 -- 10
C***                EVAL      amount2 = amount1 -* 10
C***                EVAL      amount2 = amount1 -/ 10
C                   EVAL      amount2 = amount1 *+ 10
C                   EVAL      amount2 = amount1 *- 10
C                   EVAL      amount2 = amount1 ** 10
C***                EVAL      amount2 = amount1 */ 10
C                   EVAL      amount2 = amount1 /+ 10
C                   EVAL      amount2 = amount1 /- 10
C***                EVAL      amount2 = amount1 /* 10
C***                EVAL      amount2 = amount1 // 10

The results were as follows (commented out lines were invalid).

12
-8
-8
12
20
-20
1024
0
0

> -----Original Message-----
> From:          Peter_Vidal@pall.com [SMTP:Peter_Vidal@pall.com]
> Sent:          Friday, August 02, 2002 03:12 PM
> To:            rpg400-l@midrange.com
> Subject:               RE: Error in the EVAL Statement? (when + is used
more than once)
>
>
> "I think it's taking the second + as a sign."
>
> That may be the reason Jim.  I also tried the * and it is a error. I
think this
> clarifies my doubt on this matter.
> However, I tried this now:
>
> c                   z-add     502.34        amount1           7 2
> c                   z-add     0             amount2           7 2
>
> c                   eval      amount2 = amount1 + + 7
> c                             500.00
>
> c                   seton
>
> You know the result? 8002.34
>
> How?
> Peter Vidal
> PALL Aeropower Corp.
> Senior Programmer Analyst
>
> _______________________________________________
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