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c eval amount2 = amount1 + + 7 c 500.00 becomes c eval amount2 = amount1 + + 7500.00 and 502.34 + 7500.00 = 8002.34. Would do the same thing with one + there. Regards, Jim Langston -----Original Message----- From: Peter_Vidal@pall.com [mailto:Peter_Vidal@pall.com] That may be the reason Jim. I also tried the * and it is a error. I think this clarifies my doubt on this matter. However, I tried this now: c z-add 502.34 amount1 7 2 c z-add 0 amount2 7 2 c eval amount2 = amount1 + + 7 c 500.00 c seton You know the result? 8002.34 How?
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