Re: Eval(h)

[Kyle Collie <kcollie@xxxxxxxxx>]

The 11.77815 was fictional to illustrate what I expected to be rounded
to 11.78.

On 5/19/05, Booth Martin <booth@xxxxxxxxxxxx> wrote:
> Can you post the math that provided 11.77815?  This expression has no
> provision for that, so far as I can see?  You have a 7 digit number from a 9
> digit number, which says to me you have lopped off the last two places in
> your 9/0 field.   ( (912/100) = 9  )  and that can change the results quite
> a bit.
> 
> ---------------------------------
> Booth Martin
> http://www.martinvt.com
> ---------------------------------
> -------Original Message-------
> 
> From: RPG programming on the AS400 / iSeries
> Date: 05/19/05 08:00:13
> To: Midrange RPG List
> Subject: Eval(h)
> 
> In free-form code, I have:
> 
> eval(h) 5,2field    = 9,2field / (9,0field /100);
> 
> It is not rounding up. For example, a result of 11.77815... is
> truncated to 11.77, not the expected (at least expected by me) 11.78.
> 
> What am I missing?
> 
> Kyle
> 
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