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Once again I am in your Debt Scott. Thank you thank you, -----Original Message----- From: Scott Klement [mailto:klemscot@klements.com] Sent: Wednesday, February 20, 2002 3:12 PM To: 'midrange-l' Subject: Re: SSL Socket Client Hi Chris, > What is currently eluding me is a constant defined as: > #define SSL_ENCRYPT_MASK (1<<0) > > Ok I know it is a constant but what value does (1<<0) return? Short answer: 1 Long answer: The << operator shifts the bits to the left. x<<y would shift the bits in x to the left y positions. IBM documents this here: http://publib.boulder.ibm.com/cgi-bin/bookmgr/BOOKS/qb3at602/5.6.6 If for example, you had "1<<2" it would look like this (in binary): before shifting: 00000001 after shifting: 00000100 The closest approximation to this in RPG is to just multiply by 2 for each position you want to shift. Thus "z = x<<y" in RPG would be "eval z = x * (2 ** y)". Now... in YOUR CASE, you have 1<<0. Stick that in our equasion. z = 1 * (2 ** 0). Ummm... z = 1. Shifting it zero positions does not change the value! (except possibly rounding, if there are precision issues) So, in RPG you'd define it as: D SSL_ENCRYPT_MASK... D C CONST(1)
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