Re: EXPORTing procedures

This is my take on what the program should look like.

It seems like you should have a prototype declared for the Main Procedure
to declare the program name and
that you should have dcl-pi and end-pi after the dcl-proc. Not sure why
it would compile without them.

**Free
Ctl-Opt DftActGrp(*No) ActGrp(*New) Main(Proc1);

dcl-pr Proc1 ExtPgm('Pgm1') end-pr;

dcl-proc Proc1;
dcl-pi *N end-pi;

Dsply 'In main Proc' *REQUESTER;
Proc2();
Return;
end-proc;

dcl-proc Proc2;
dcl-pi *N end-pi;

Dsply 'In Proc2' '*REQUESTER';
Return;
end-proc;

On Thu, Nov 12, 2020 at 10:18 AM Brian Parkins <goodprophet.bp@xxxxxxxxx>
wrote:

Here's a puzzle. Does anyone have a good explanation? I have a source
member containing two procedures - the main (entry) procedure and a
subprocedure (PROC2). The main procedure calls the subprocedure.

If I code this as a Cycle Main program, all works well. Example:

**Free
Ctl-Opt DftActGrp(*No) ActGrp(*New);
// Main Entry procedure
Dcl-PR Proc2;
End-PR;
Dsply 'In main Proc' '*REQUESTER';
Proc2();
*InLR = *On;
Return;
Dcl-Proc Proc2;
// Internal subprocedure
Dsply 'In Proc2' '*REQUESTER';
End-Proc;

If I code this as a Linear Main program, PROC2 requires the EXPORT
keyword, e.g.

**Free
Ctl-Opt DftActGrp(*No) ActGrp(*New) Main(Proc1);
Dcl-Proc Proc1;
// Main Entry procedure
Dcl-PR Proc2;
End-PR;
Dsply 'In main Proc' '*REQUESTER';
Proc2();
Return;
End-Proc;
Dcl-Proc Proc2 Export;
// Internal subprocedure
Dsply 'In Proc2' '*REQUESTER';
End-Proc;

(The source will compile but the Bind step fails without the EXPORT
keyword - "No definition was found for reference PROC2 in *MODULE".)
Why is the EXPORT keyword required? (I've not been able to find any
clear explanation in the manual - tell me what I'm missing.)

FOOTNOTE: If I modified the coding of the second example and EXPORTed
PROC1, I could then create a *SRVPGM which did /not/ require PROC2 to be
EXPORTED. Odd!

Brian.
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