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And if you want to retain the leading zeros,:

EvalR CONSNO = %TRIMR(%EDITC(Partner#: 'X' ));

On Nov 30, 2007 12:40 PM, Francis Lapeyre <flapeyre@xxxxxxxxx> wrote:

If you want to supress leading zeros and right-justify in the CONSNO
field:

EvalR CONSNO = %TRIMR(%EDITC(Partner#: 'Z' ));

In this case, you need to use EvalR.

On Nov 30, 2007 12:33 PM, Gene Burns <burns.gene@xxxxxxxxx> wrote:

You could also use a data structure overlay like I used in this service
program (SETSIGN) which converts to character and places the sign on the

right or left as chosen.

http://code.midrange.com/503ae72d81.html

Gene

On Nov 30, 2007 12:03 PM, CRPence <crp@xxxxxxxxxxxxxxxxxxxx> wrote:

EDTCDE(X) is offered up quickly and often for this common inquiry,
but generally without anyone ever having stated [what IMO is a *huge*]
caveat; i.e. that the X edit code is *not* /good/ for presentation of
negative values.

I would suggest instead, since the EDTWRD was enhanced specifically
to enable this type of output, one of:
EDTWRD('0 ') if no sign is desired
EDTWRD('0 -') if right negative sign is desired
EDTWRD('0- ') if left negative sign is desired.

Regards, Chuck
--
All comments provided "as is" with no warranties of any kind
whatsoever and may not represent positions, strategies, nor views of
my
employer

Michael_Schutte@xxxxxxxxxxxx wrote:
%EditC(partner:'X')

Mike A wrote:
CONSNO = %CHAR(Partner#);

Consno is 8A
Partner# 8S 0 and has a value of 00012345

When Statement CONSNO = %CHAR(Partner#); is executed the Value of
CONSNO
is 12345bbb (b=Blank)

How can I get the Value of CONSNO to = 00012345

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--
Francis Lapeyre

Solum potestis prohibere ignes silvarum.





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