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After having removed the duplicates
... what about adding either a unique key constraint or an unique index to
the file for avoiding future duplicates?

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"

-----Ursprüngliche Nachricht-----
Von: MIDRANGE-L [mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von John
McKee
Gesendet: Tuesday, 24.2 2015 21:56
An: Midrange Systems Technical Discussion
Betreff: Re: Locate duplicate accounts in a file

ORDER BY turned out not to be essential. Only five records to deal with.
Definitely nice to know the proper syntax, especially if there had been a
lot more to deal with. Not sure yet, but the duplicates >might< have been
there due to a field that had been forced to a number 1 - a cycle count.
File was prepared elsewhere.

Thanks.

John McKee

On Tue, Feb 24, 2015 at 2:25 PM, Scott Mildenberger <
SMildenberger@xxxxxxxxxxxxxxxxxx> wrote:

with a as (
select siacct, count(siacct) as cnt
from spbsobdp group by siacct)
select * from a where cnt > 1 order by siacct

Scott


-----Original Message-----
From: MIDRANGE-L [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of
John McKee
Sent: Tuesday, February 24, 2015 1:19 PM
To: Midrange Systems Technical Discussion
Subject: Locate duplicate accounts in a file

I have a file that is supposed to have one record per account number.
There is at least one duplicate account in the file.

I'm thinking there is a simple(?) way to locate the duplicates with SQL.
But, I am missing something.

I have select siacct, count(siacct) from spbsobdp group by siacct
order by siacct

Which produces a nice list. How can I change the output so only those
records with count > 1 show?

My first thought is to redirect to a file and then query that. Is
there another option?

John McKee
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