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Such a simple concept. Not having much need for SQL ( sinking ship here),
that did not enter my mind to even look. Then, again, not sure if v5r4 has
that, and another person is actually editing the file now. But, I am going
to try this on a fresh copy of the file.

Thanks Rob.

John McKee

On Tue, Feb 24, 2015 at 2:28 PM, <rob@xxxxxxxxx> wrote:

Close, just one more clause, HAVING.

select siacct, count(siacct) as siacctNbr
from spbsobdp
group by siacct
order by siacct
having count(siacct)>1

Rob Berendt
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Group Dekko
Dept 1600
Mail to: 2505 Dekko Drive
Garrett, IN 46738
Ship to: Dock 108
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Kendallville, IN 46755
http://www.dekko.com





From: John McKee <jmmckee@xxxxxxxxxxxxxx>
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxx>
Date: 02/24/2015 03:19 PM
Subject: Locate duplicate accounts in a file
Sent by: "MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx>



I have a file that is supposed to have one record per account number.
There is at least one duplicate account in the file.

I'm thinking there is a simple(?) way to locate the duplicates with SQL.
But, I am missing something.

I have select siacct, count(siacct) from spbsobdp group by siacct order by
siacct

Which produces a nice list. How can I change the output so only those
records with count > 1 show?

My first thought is to redirect to a file and then query that. Is there
another option?

John McKee
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