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Try the following
select siacct, count(siacct) from spbsobdp group by siacct
having count(siacct) > 1
order by siacct
Alan Shore
E-mail : ASHORE@xxxxxxxx
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Phone [C] : (631) 880-8640
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-----Original Message-----
From: MIDRANGE-L [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of John McKee
Sent: Tuesday, February 24, 2015 3:19 PM
To: Midrange Systems Technical Discussion
Subject: Locate duplicate accounts in a file
I have a file that is supposed to have one record per account number.
There is at least one duplicate account in the file.
I'm thinking there is a simple(?) way to locate the duplicates with SQL.
But, I am missing something.
I have select siacct, count(siacct) from spbsobdp group by siacct order by siacct
Which produces a nice list. How can I change the output so only those records with count > 1 show?
My first thought is to redirect to a file and then query that. Is there another option?
John McKee
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