Re: Locate duplicate accounts in a file

[John McKee <jmmckee@xxxxxxxxxxxxxx>]

ORDER BY turned out not to be essential.  Only five records to deal with.
Definitely nice to know the proper syntax, especially if there had been a
lot more to deal with.  Not sure yet, but the duplicates >might< have been
there due to a field that had been forced to a number 1 - a cycle count.
File was prepared elsewhere.

Thanks.

John McKee

On Tue, Feb 24, 2015 at 2:25 PM, Scott Mildenberger <
SMildenberger@xxxxxxxxxxxxxxxxxx> wrote:

> with a as (
> select siacct, count(siacct) as cnt
> from spbsobdp group by siacct)
> select * from a where cnt > 1 order by siacct
>
> Scott
>
>
> -----Original Message-----
> From: MIDRANGE-L [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of
> John McKee
> Sent: Tuesday, February 24, 2015 1:19 PM
> To: Midrange Systems Technical Discussion
> Subject: Locate duplicate accounts in a file
>
> I have a file that is supposed to have one record per account number.
> There is at least one duplicate account in the file.
>
> I'm thinking there is a simple(?) way to locate the duplicates with SQL.
> But, I am missing something.
>
> I have select siacct, count(siacct) from spbsobdp group by siacct order by
> siacct
>
> Which produces a nice list.  How can I change the output so only those
> records with count > 1 show?
>
> My first thought is to redirect to a file and then query that.  Is there
> another option?
>
> John McKee
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