Re: HVLPTASK

["Steve Richter" <srichter@xxxxxxxxxxxxx>]

good explanation, Andy.  Thank you.

----- Original Message -----
From: "Andy Nolen-Parkhouse" <aparkhouse@mediaone.net>
To: <midrange-l@midrange.com>
Sent: Tuesday, January 08, 2002 1:15 PM
Subject: RE: HVLPTASK


> Steve,
>
> The coders wanted to display the percent of available CPU used.  Their
> normal algorithms are based upon an entire CPU.  If a job was using 10%
> of a physical processor in a partition which was allocated 40% of that
> CPU, then the job is using 25% of available CPU.  By creating artificial
> usage of an additional 15%, the total used (10% + 15% = 25%) accurately
> reflects how much of the available system in that partition is being
> used.
>
> I'm not familiar with the term 'processor multiple'.
>
> Best regards,
> Andy Nolen-Parkhouse
>
> > > In the example you use above, if a job was using 10% of the
> > > physical CPU in a partition which was allocated 40%:
> > >
> > > The job would show up as 10%
> > > The task would show up as 15% (assuming that no other work was on
> the
> > > system)
> > >
> > > Thus the total system used would be displayed as 25%, which would be
> the
> > > equivalent of 10/40.
> > >
> >
> > In my scenario P1 has 40% of the cpu, P2 has 60%.  Job 1 runs in P1
> and
> > uses
> > 10% of the total cpu or 25% of the P1's cpu.  Why does the task/job
> show
> > up
> > as 15% ?
> >
> > In my 40/60 split, what is the processor multiple ?
> >
> > Thanks,
> >
> > Steve Richter
>
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