----- Original Message -----
From: "Andy Nolen-Parkhouse" <aparkhouse@mediaone.net>
>
> I think the task is in there just to make the math work, but not in the
> way you're suggesting above.  All the metrics used to calculate the
> percentage of processor used are calculated against complete processor
> multiples.  In the example you use above, if a job was using 10% of the
> physical CPU in a partition which was allocated 40%:
>
> The job would show up as 10%
> The task would show up as 15% (assuming that no other work was on the
> system)
>
> Thus the total system used would be displayed as 25%, which would be the
> equivalent of 10/40.
>

In my scenario P1 has 40% of the cpu, P2 has 60%.  Job 1 runs in P1 and uses
10% of the total cpu or 25% of the P1's cpu.  Why does the task/job show up
as 15% ?

In my 40/60 split, what is the processor multiple ?

Thanks,

Steve Richter





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