The coders wanted to display the percent of available CPU used.  Their
normal algorithms are based upon an entire CPU.  If a job was using 10%
of a physical processor in a partition which was allocated 40% of that
CPU, then the job is using 25% of available CPU.  By creating artificial
usage of an additional 15%, the total used (10% + 15% = 25%) accurately
reflects how much of the available system in that partition is being

I'm not familiar with the term 'processor multiple'.

Best regards,
Andy Nolen-Parkhouse

> > In the example you use above, if a job was using 10% of the
> > physical CPU in a partition which was allocated 40%:
> >
> > The job would show up as 10%
> > The task would show up as 15% (assuming that no other work was on
> > system)
> >
> > Thus the total system used would be displayed as 25%, which would be
> > equivalent of 10/40.
> >
> In my scenario P1 has 40% of the cpu, P2 has 60%.  Job 1 runs in P1
> uses
> 10% of the total cpu or 25% of the P1's cpu.  Why does the task/job
> up
> as 15% ?
> In my 40/60 split, what is the processor multiple ?
> Thanks,
> Steve Richter

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