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SQL stmt to load a commonly used date format



fixed

I have a 6 character field named "todaysDate" that I want to load with today's date using SQL.

The stmt below works well, but one would think that there should be a much simpler stmt to load a commonly used date format.

Is there a simpler SQL stmt?

Thanks




update myFile set todaysDate = right(replace(char(current date,iso),'-',''),6)



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