Re: Help with %Dec

[Vern Hamberg <vhamberg@xxxxxxxxxxx>]

more like

%dec((%subst(char : 1 : 7) + '.' + %subst(char : 8 : 4)) : 11 : 4)

Maybe? As Brian said, the decimal point has to be there.

Vern

On 3/24/2011 9:48 AM, Jerry C. Adams wrote:
> Try %dec(char:7:4)
>
> Jerry C. Adams
> IBM i Programmer/Analyst
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> -----Original Message-----
> From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx]
> On Behalf Of Jeff Young
> Sent: Thursday, March 24, 2011 9:30 AM
> To: rpg400-l@xxxxxxxxxxxx
> Subject: Help with %Dec
>
> Given an 11 char field with the value of '00000639000', I am attempting to
> use
> %Dec to convert it to an 11.4 position numeric field.
> new_value = %dec(char : 11 : 4).
> I *want* the result to be 63.9000, but am getting 639000.0000 as my result.
> What am I not understanding about how this works, and what would be the best
> way
> to get the desired result.
>
> TIA,
>   
> Jeff Young
> Sr. Programmer Analyst
> IBM -e(logo) server Certified Systems Exper - iSeries Technical Solutions
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