RE: Help with %Dec

%dec(char : 11 : 4) the 4 represents the precision you wish in the result.

So you are actually getting the value 00000639000.0000 with the precision of
4 decimal positions.

Where the 4 comes in to play is when you desire a certain amount of
precision in your calculation.

Lets pretend pi = 22 / 7.

area = (22 / 7) * r^2

If you want 22 / 7 to be accurate to 4 decimals then
Area = %Decimal((22 / 7): 4) * r^2.

If you want 22 / 7 to be accurate to 10 decimals then
Area = %Decimal((22 / 7): 10) * r^2.


What you want is something like my_result = %dec(my_string) / 4



-----Original Message-----
From: Jeff Young [mailto:cooljeff913@xxxxxxxxx]
Sent: Thursday, March 24, 2011 10:30 AM
To: rpg400-l@xxxxxxxxxxxx
Subject: Help with %Dec

Given an 11 char field with the value of '00000639000', I am attempting to
use
%Dec to convert it to an 11.4 position numeric field.
new_value = %dec(char : 11 : 4).
I *want* the result to be 63.9000, but am getting 639000.0000 as my result.
What am I not understanding about how this works, and what would be the best
way
to get the desired result.

TIA,
 
Jeff Young
Sr. Programmer Analyst
IBM -e(logo) server Certified Systems Exper - iSeries Technical Solutions
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