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What you want is something like my_result = %dec(my_string) / 4
Duh.....
my_result = %dec(my_string) / 1000
-----Original Message-----
From: Jeff Young [mailto:cooljeff913@xxxxxxxxx]
Sent: Thursday, March 24, 2011 10:30 AM
To: rpg400-l@xxxxxxxxxxxx
Subject: Help with %Dec
Given an 11 char field with the value of '00000639000', I am attempting to
use
%Dec to convert it to an 11.4 position numeric field.
new_value = %dec(char : 11 : 4).
I *want* the result to be 63.9000, but am getting 639000.0000 as my result.
What am I not understanding about how this works, and what would be the best
way
to get the desired result.
TIA,
Jeff Young
Sr. Programmer Analyst
IBM -e(logo) server Certified Systems Exper - iSeries Technical Solutions
V5R2
IBM Certified Specialist- e(logo) server i5Series Technical Solutions
Designer V5R3
IBM Certified Specialist- e(logo)server i5Series Technical
Solutions Implementer V5R3
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