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Cor, You're probably correct. I just checked and this works too, which makes sense. FOR Idx = 1 TO %Int( %Elem( A ) / %Elem( B )) ; -mark
A division is not an integer value (might end up as 1,5). The FOR loop only works with integer values as starting and ending values. %DIV returns an integer value. But, then again, I might be wrong. Cor-----Original Message----- From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of M. Lazarus Sent: woensdag 20 december 2006 3:49 To: RPG400-L@xxxxxxxxxxxx Subject: Compiler debug or undocumented limitation? This code will not compile, despite the manual saying that an expression is valid: D A S 1a Dim( 100 ) D B S 1a Dim( 25 ) D Idx S 5u0 /Free FOR Idx = 1 TO %Elem( A ) / %Elem( B ) ; ENDFOR ; *INLR = *On ; /End-Free Changing this line from: FOR Idx = 1 TO %Elem( A ) / %Elem( B ) ; to: FOR Idx = 1 TO %Div( %Elem( A ): %Elem( B )) ; satisfies the compiler. Adding parentheses to the first example doesn't help. Can someone explain why the first one is invalid? -mark
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