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D A S 1a Dim( 100 ) D B S 1a Dim( 25 ) D Idx S 5u0 /Free FOR Idx = 1 TO %Elem( A ) / %Elem( B ) ; ENDFOR ; *INLR = *On ; /End-Free Changing this line from: FOR Idx = 1 TO %Elem( A ) / %Elem( B ) ; to: FOR Idx = 1 TO %Div( %Elem( A ): %Elem( B )) ;satisfies the compiler. Adding parentheses to the first example doesn't help. Can someone explain why the first one is invalid?
-mark
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