|
I wonder what happens if you put the Amt * -1 in parentheses? C Eval ExtPrice$ = %editc((Amt * -1): 'J': '$') Kurt Anderson wrote:
Amt is 9s,2ExtPrice$ is 14a Amt = 50 C Eval Amt *= -1C Eval ExtPrice$ = %editc( Amt: 'J': '$' )Results as $50.00-. Which is what I want to see.C Eval ExtPrice$ = %editc(Amt * -1: 'J': '$')Results as $50.00. (no minus sign) Why is this? What am I missing? Something about the intermediate result of the expression? Thanks,Kurt AndersonApplication Developer Highsmith Inc. W5527 State Road 106, P.O. Box 800 Fort Atkinson, WI 53538-0800 TEL (920) 563-9571 FAX (920) 563-7395 EMAIL kjanderson@xxxxxxxxxxxxx
As an Amazon Associate we earn from qualifying purchases.
This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.