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Kurt, %EDITC always returns the same length character value, regardless of the value of the input numeric value. When you had a 9S2 value with the 'J' edit code, it could return: '9,999,999.99-' If I counted right, that means 13 possible characters are always returned. However, by adding the '$' to the mix, an additional character is included: '$9,999,999.99-' Thus 14-positions are always returned. Now, when you added a multiplication, the best case scenario would be for it to return 15-position. Why? Because A*B cold produce a 10-digit value. The code for %EDITC is generated at compile-time, therefore it has to do a best guess as to the size. You can determine the size the compiler is using, but doing this: D myTest S 50A myTest = 'X' + %editc(Amt * -1: 'J': '$') + 'X'; Then look at myTest in debug and count the characters between the "X...X". That length is always returned. Obviously if you MOVE-RIGHT using EVALR, you get the status/minus sign, however you have the possibility of stripping off the leading dollar sign. -Bob Cozzi www.iSeriesTV.com Ask your Manager to watch iSeriesTV.com -----Original Message----- From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Kurt Anderson Sent: Monday, September 11, 2006 1:17 PM To: RPG programming on the AS400 / iSeries Subject: %editc an expression Amt is 9s,2 ExtPrice$ is 14a Amt = 50 C Eval Amt *= -1 C Eval ExtPrice$ = %editc( Amt: 'J': '$' ) Results as $50.00-. Which is what I want to see. C Eval ExtPrice$ = %editc(Amt * -1: 'J': '$') Results as $50.00. (no minus sign) Why is this? What am I missing? Something about the intermediate result of the expression? Thanks, Kurt Anderson Application Developer Highsmith Inc. W5527 State Road 106, P.O. Box 800 Fort Atkinson, WI 53538-0800 TEL (920) 563-9571 FAX (920) 563-7395 EMAIL kjanderson@xxxxxxxxxxxxx
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