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That worked.  What does the (r) do?  Retain precision?

Ron Power
Programmer
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P.O. Box 908
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"Barton, Mike" <Mike.Barton@xxxxxxxxxxxxxxxxx> 
Sent by: rpg400-l-bounces@xxxxxxxxxxxx
19/05/2005 11:02 AM
Please respond to
RPG programming on the AS400 / iSeries <rpg400-l@xxxxxxxxxxxx>


To
"'RPG programming on the AS400 / iSeries'" <rpg400-l@xxxxxxxxxxxx>
cc

Subject
RE: Eval(h)






>In free-form code, I have:
>
>eval(h) 5,2field    = 9,2field / (9,0field /100);
>
>It is not rounding up. For example, a result of 11.77815... is
>truncated to 11.77, not the expected (at least expected by me) 11.78.
>
>What am I missing?

Kyle
                 just a guess but...

whenever using eval with numbers of different decmal places,
best to use the opcode extender of r
eg eval(hr) 5,2field.....

HTH

Mike

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