Re: Half-Adjust with /free -- RPG400-L

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Subject: Re: Half-Adjust with /free
From: Mike Wills <koldark@xxxxxxxxx>
Date: Tue, 22 Jun 2004 10:21:49 -0500
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Try eval (h) val = val1 + val2;

On Tue, 22 Jun 2004 10:15:48 -0500, michaelr_41@xxxxxxxxxxxxxx wrote:
> 
> I can't believe I haven't encoutered this yet. How does one perform
> half-adjust when using free format?
> 
> /free
>   a =(H) b + c;
> 
> doesn't seem to work. Do I need to do a %DECH or something?

-- 
Mike Wills
iSeries Programmer/Lawson Administrator
koldark@xxxxxxxxx
http://www.koldark.net

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