RE: %EQUAL in a DOU loop

It appears to me that this is in a loop because you are continuously doing a
SETLL to the file.  You are not progressing through the records.  You would
need to do a READE to work your way through the records and eventually get
to the end.

Your code might look like this.

C                   EVAL      KF_LINE = 0
 *
 * Set File Pointer
C     FILEKEY15     SETLL     FILE15
 *
 * Notes Records Exist in File
C                   IF        %EQUAL(FILE15)
 *
 * Find New Line # for Note #
C                   DOU       %EOF(FILE15)
C     FILEKEY15     READE     FILE15
 *
C                   IF        %EOF(FILE15)
C                   LEAVE
C                   ELSE
 *
C                   EVAL      KF_LINE = KF_LINE + 1
C                   ENDIF
 *
C                   ENDDO
C                         ENDIF

Hope this helps.

Dawn Siegrist
Sr. Programmer/Analyst
Penske Truck Leasing Co.
610-775-6243
Dawn.Siegrist@xxxxxxxxxx


-----Original Message-----
From: fkany@xxxxxxxxxxxxxxxxxx [mailto:fkany@xxxxxxxxxxxxxxxxxx]
Sent: Thursday, November 20, 2003 11:35 AM
To: RPG400-L@xxxxxxxxxxxx
Subject: %EQUAL in a DOU loop



Hello,

The program seems to crash in the routine below.  I know that there aren't
any records with 999 lines of notes.  I'm thinking that maybe the program
keeps looping.
Am I missing something in the code below that would cause this routine to
keep looping?

The program crashes with this message, "Receiver value too small to hold
result.
The target for a numeric operation is too small to hold the result"

Thanks,

Frank

C                   EVAL      KF_LINE = 1
 *
 * Set File Pointer
C     FILEKEY15     SETLL     FILE15
 *
 * Notes Records Exist in File
C                   IF        %EQUAL(FILE15)
 *
 * Find New Line # for Note #
C                   DOU       NOT %EQUAL(FILE15)
C     FILEKEY15     SETLL     FILE15
 *
C                   IF        NOT %EQUAL(FILE15)
C                   LEAVE
C                   ENDIF
 *
C                   IF        %EQUAL(FILE15)
C                   EVAL      KF_LINE = KF_LINE + 1
C                   ENDIF
 *
C                   ENDDO

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