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Htimfmt(*hms) D starttime s t inz(t'16:26:57') D endtime s t inz(t'18:09:04') D diff s t /free diff = t'00:00:00' + %diff(endtime : starttime : *seconds); dsply diff; *inlr = *on; /end-free
Mel Rothman Mel Rothman, Inc.
I have two date fields *MDY with these values. '18:09:04' and '16:26:57'. All I want to do is find the total elapsed time in hours,minutes and seconds between them.
I'm using the SUBDUR like this;
EndTime SUBDUR StartTime Hour:*H EndTime SUBDUR StartTime Minute:*MN EndTime SUBDUR StartTime Second:*S
Hour,Minute and second are part of a 6,0 data structure. When I put my program in debug my 'elapsed' variable contains 010227. I suspect its because of negatives I'm getting the minutes and seconds the way I am.
What am I missing here? (Should I be doing this differently then SUBDUR?)
Andy
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