A left outer join returns all rows from the first table.
If there is no match in the second table NULL values are returned

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"
?Train people well enough so they can leave, treat them well enough so they
don't want to.? (Richard Branson)


-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Rob
Berendt
Sent: Freitag, 20. Dezember 2019 13:20
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxxxxxxxx>
Subject: RE: Help with SQL

I did a simple google for sql list missing child rows Basically it boiled
down to a few choices between NOT EXISTS NOT IN LEFT OUTER JOIN EXCEPTION
JOIN

Rob Berendt
--
IBM Certified System Administrator - IBM i 6.1 Group Dekko Dept 1600 Mail
to: 2505 Dekko Drive
Garrett, IN 46738
Ship to: Dock 108
6928N 400E
Kendallville, IN 46755
http://www.dekko.com


-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Vinay
Gavankar
Sent: Friday, December 20, 2019 7:14 AM
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxxxxxxxx>
Subject: Help with SQL

CAUTION: This email originated from outside of the organization. Do not
click links or open attachments unless you recognize the sender and know the
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Hi,

We have a Table with K1, K2, K3, K4 as Primary keys with about 800 million
records. A child table, which is partitioned, has K1, K2, K3, K4, K5 (Seq
Number) as Primary keys and a Status field (value of A or I) with about 10
billion records. Child table having no record for the 4 keys is possible,
though highly unlikely.

I need to get a list of records (just the key fields) from the main Table,
which has no record in the child table with Status = 'A' (may or may not
have an 'I' Status record).

Can someone please help me with some efficient sql code to achieve this?
TIA.

Vinay
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