Re: EVAL var *=

I'll expect rotten tomatoes tossed at me for this!! :)

This is like the fixed-format MULT opcode, without specifying Factor 1, as
described here:

If factor 1 is not specified, factor 2 is multiplied by the result field

and the product is placed in the result field.

Ducking now with raingear on!

Vern


On 4/11/2018 9:24 AM, Christopher Bipes wrote:

Multiplies two numbers and sets a value to the result of the operation.
For example, if a variable @x equals 35, then @x *= 2 takes the original
value of @x, multiplies by 2 and sets @x to that new value (70).


Chris Bipes
Director of Information Services
CrossCheck, Inc.

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxx> On Behalf Of
Versfelt, Charles
Sent: Wednesday, April 11, 2018 7:22 AM
To: midrange-l@xxxxxxxxxxxx
Subject: EVAL var *=

Checking a program that bombed, I came across this line of code.
C eval @CurrOptFntSiz *= (1+(@PzFactor*.01))

I don't think I recall seeing *= in an eval statement.
The compiler certainly accepted it.
Is this multiplying @CurrOptFntSize by (1+(@PzFactor*.01)) and setting
@CurrOptFntSize equal to that?

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