Re: EVAL var *=

No tomatoes from me Vern.

This is the way I teach it now. Originally I didn't like the short-form
notation - then I realized that nobody ever coded X ADD 1 X they coded ADD
1 X - the short-form X += 1 is the equivalent with the result up front as
with all the eval operations.


Jon Paris

www.partner400.com
www.SystemiDeveloper.com

On Apr 11, 2018, at 12:07 PM, Vernon Hamberg <vhamberg@xxxxxxxxxxxxxxx>

wrote:

I'll expect rotten tomatoes tossed at me for this!! :)

This is like the fixed-format MULT opcode, without specifying Factor 1,

as described here:

If factor 1 is not specified, factor 2 is multiplied by the result

field and the product is placed in the result field.

Ducking now with raingear on!

Vern

On 4/11/2018 9:24 AM, Christopher Bipes wrote:

Multiplies two numbers and sets a value to the result of the operation.

For example, if a variable @x equals 35, then @x *= 2 takes the original
value of @x, multiplies by 2 and sets @x to that new value (70).

Chris Bipes
Director of Information Services
CrossCheck, Inc.

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxx> On Behalf Of

Versfelt, Charles

Sent: Wednesday, April 11, 2018 7:22 AM
To: midrange-l@xxxxxxxxxxxx
Subject: EVAL var *=

Checking a program that bombed, I came across this line of code.
C eval @CurrOptFntSiz *= (1+(@PzFactor*.01))

I don't think I recall seeing *= in an eval statement.
The compiler certainly accepted it.
Is this multiplying @CurrOptFntSize by (1+(@PzFactor*.01)) and setting

@CurrOptFntSize equal to that?

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