RE: 5250 telnet keepalive

Charles,

I'm sorry I misspoke. I am using telnet. I telnet to machine A which
bridges me to machine B. I won't go into the details of why it has to
happen this way but it does. It shouldn't make any difference since the
bridge program just transfers the TCP/IP packets back and forth.

Albert

  ----- Original Message -----
  From: "Wilt, Charles"
  To: "Midrange Systems Technical Discussion"
  Subject: RE: 5250 telnet keepalive
  Date: Wed, 21 Sep 2005 08:35:15 -0400


  Albert,

  When you say you can't use pass-through, I assume you mean the
  STRPASTHR command.

  Have you tried simply using telnet from the first machine to the
  second?

  TELNET secondmachinename

  or

  TELNET xxx.xxx.xxx.xxx


  I can think of no reason why this wouldn't work or couldn't be used.


  HTH,

  Charles Wilt
  --
  iSeries Systems Administrator / Developer
  Mitsubishi Electric Automotive America
  ph: 513-573-4343
  fax: 513-398-1121


  > -----Original Message-----
  > From: midrange-l-bounces@xxxxxxxxxxxx
  > [mailto:midrange-l-bounces@xxxxxxxxxxxx]On Behalf Of Albert York
  > Sent: Monday, September 19, 2005 5:43 PM
  > To: midrange-l@xxxxxxxxxxxx
  > Subject: 5250 telnet keepalive
  >
  >
  > I have a situation where my telnet seesions keep timing out. For
  various
  > reason, which are not pertinent here, it is necessary for me to
  access
  > the AS/400 through another AS/400 and I can't use the passthrouhg
  > capability. So I have written a TCP/IP bridge program to accomplish
  which
  > has two sockets open and forwards whatever it receives on one
  socket to
  > the other socket. It works quite well except for the timeout
  problem.
  > After 15 minutes or so of inactivity the connection just hangs and
  I have
  > to disconnect and reconnect.
  >
  > I would like to know if there is some UDDS string (like a poll)
  that my
  > bridge program could send to either the AS/400 or the terminal
  emulation
  > program which would keep the connection alive but would not effect
  the
  > job in any way.
  >
  > Thank you,
  >
  > Albert York
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