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That would work but I'd rather see select vendor, vndname, vndad1, vndad2, vndad3, vstate, vpost, vdtlpd, count(abvnd) from bpcsf/avm join bpcsf/abr on vendor = abvnd where absts <> 'W' group by vendor, vndname, vndad1, vndad2, vndad3, vstate, vpost, vdtlpd order by vendor or using a more readable more on the inner join select vendor, vndname, vndad1, vndad2, vndad3, vstate, vpost, vdtlpd, count(abvnd) from bpcsf/avm, bpcsf/abr where vendor = abvnd and absts <> 'W' group by vendor, vndname, vndad1, vndad2, vndad3, vstate, vpost, vdtlpd order by vendor Since there is only be one record for each vendor, you can group by all fields selected from the vendor master (AVM) without affecting the query. Using the MAX function, while returning the same results would imply that there are or at least could be multiple records for each vendor in the vendor master file. HTH, Charles > -----Original Message----- > From: rick.baird@xxxxxxxxxxxxxxx [mailto:rick.baird@xxxxxxxxxxxxxxx] > Sent: Friday, February 13, 2004 4:35 PM > To: Midrange Systems Technical Discussion > Subject: Re: SQL question with subselect > > > > I should read the entire message before answering :( > > >In a group by situation in a sub query, it seems that I can > have only one > >column selected. Obviously without the count by vendor, the > report is > >useless so how do I get that count & vendor number? > > something like this: > > select distinct vendor, > max(vndnam), max(vndad1), > max(vndad2), max(vndad3), > max(vstate), max(vpost), > max(vdtlpd), count(abvnd) > from bpcsf/avm > join bpcsf/abr > on vendor = abvnd > group by abvnd > > > _______________________________________________ > This is the Midrange Systems Technical Discussion > (MIDRANGE-L) mailing list > To post a message email: MIDRANGE-L@xxxxxxxxxxxx > To subscribe, unsubscribe, or change list options, > visit: http://lists.midrange.com/mailman/listinfo/midrange-l > or email: MIDRANGE-L-request@xxxxxxxxxxxx > Before posting, please take a moment to review the archives > at http://archive.midrange.com/midrange-l. >
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