RE: V4R5?

Chris,

What you answered would seem to make sense.  But note the 2-byte binary
fields are limited in DDS to holding 4-digit numbers (9,999) even though
256**2 = 65,536.  4-byte binary fields are limited to 9-digit numbers even
though 256**4 = 4,294,967,296.  I guess this means that 8-byte binary fields
will be limited to a 19-digit number?  I'm looking for confirmation of my
suspicions.

William K. Reger
Senior Project Manager
Levitz Furniture Corporation
Phone:  (561) 994-5114
E-mail:  breger@levitz.com <mailto:breger@levitz.com> 

                -----Original Message-----
                From:   Chris Bipes [mailto:rpg@cross-check.com]
                Sent:   Wednesday, April 12, 2000 10:00 AM
                To:     'MIDRANGE-L@midrange.com'
                Subject:        RE: V4R5?

                256**8=18446744073709551616

                Christopher K. Bipes     mailto:ChrisB@Cross-Check.com

                -----Original Message-----
                From: Reger, Bill [mailto:breger@levitz.com]
                Sent: Wednesday, April 12, 2000 5:15 AM
                To: 'MIDRANGE-L@midrange.com'
                Subject: RE: V4R5?

                One thing I've heard is that V4R5 will include 8-byte binary
field support.
                Does anyone (are you listening IBM?) know what the biggest
number will be
                that will fit in an 8-byte binary field?  I need the value
to enhance WRKDBF
                to support these biggies.

                William K. Reger
                Senior Project Manager
                Levitz Furniture Corporation
                Phone:  (561) 994-5114
                E-mail:  breger@levitz.com <mailto:breger@levitz.com> 

                
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