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Which tells me that "technically" a prototype is _not_ required, it just makes it easier to write the compiler. A multi-pass compiler could simply flag the point where it found the function|procedure call, keep going until it found the definition of the procedure, which includes the procedure interface which has the same information as the prototype. It could then go back and insert the code for the function|procedure call and make sure it's being called with the correct parameters. From: Jim Langston <jlangston@conexfreight.com> > Answer: The compiler requires it to compile. <big snip> > +--- > | This is the Midrange System Mailing List! > | To submit a new message, send your mail to MIDRANGE-L@midrange.com. > | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. > | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. > | Questions should be directed to the list owner/operator: david@midrange.com > +--- __________________________________________________ Do You Yahoo!? Talk to your friends online with Yahoo! Messenger. http://im.yahoo.com +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +---
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