Zip file question...

Shane,

ZipEntry.getName() will return the full path name of the file as it is 
stored in the zip file. So all you need to do is just pull the name apart 
with some code like:

        final ZipFile zipFile = new ZipFile(zip-file-name);
        final Enumeration zipList = zipFile.entries();
        while (zipList.hasMoreElements()) {
            final String entryPath;
            final String entryName;
            if (zipEntry.isDirectory()) {
                entryPath = zipEntry.getName();
                entryName = "";
            } else {
                final String fullPathName = zipEntry.getName();
                entryPath = fullPathName.substring(0,
                        fullPathName.lastIndexOf(File.separatorChar) + 1);
                entryName = fullPathName.substring(
                        fullPathName.lastIndexOf(File.separatorChar) + 1);
            }
        }

And if you want the all of the path elements individually, 

String [] pathElements = zipEntry.getName().split(File.separator);

should come close to doing the job.

-----Original Message-----
From: java400-l-bounces@xxxxxxxxxxxx 
[mailto:java400-l-bounces@xxxxxxxxxxxx] On Behalf Of Shane_Cessna@xxxxxxx
Sent: August 19, 2005 08:55
To: Java Programming on and around the iSeries / AS400
Subject: Zip file question...

I've got a Zip file on our IFS that I'd like to open and extract only 
certain files...you know how in WinZip, it lists the files like this:

Name   | Type    | Size    | Ratio    | Packed    | Path

I'd like to be able to extract only records with a specific Path 
attribute...I've looked all through the java.util.zip javadocs and have 
found a whole lot of nuthin...

Thanks in advance.

Shane


_________________________________________________________________
Jeff Furgal / MIMIX Product Architect / Lakeview Technology

furgalj@xxxxxxxxxxxxxxxx