|
Xu,
Don was correct, once a connection is established it will use it for the URL
also. If you have your properties set to use it. There is something about
cached passwords and signon.
Here is a test for you. See if this solves your problem. I am editing on the
fly but you get the idea and it works for me <grin>.
import java.io.File;
import java.sql.*;
import com.ibm.as400.access.*;
public class ConnectTest {
public static void main(String args[]) {
AS400 myAS400 = new AS400("MYSYSTEM");
String jdbcURL = null;
String systemName = myAS400.getSystemName();
String userID = myAS400.getUserId();
Connection c;
try {
Class.forName("com.ibm.as400.access.AS400JDBCDriver");
} catch(ClassNotFoundException e) {
System.out.println(e.toString());
}
try {
if (userID.equals("John")) {
jdbcURL = "jdbc:as400://" + systemName + "databaseJohn";
}
else
if (userID.equals("Tom")) {
jdbcURL = "jdbc:as400://mysystem/databaseTom";
}
c = DriverManager.getConnection(jdbcURL);
System.out.println("Driver connected -- Success");
c.close();
}
catch (Exception e) {
System.out.println("Driver failed - null Connection returned.");
}
System.out.println("\nConnection Test Done.");
System.exit(0);
} // end main
}
-----Original Message-----
From: java400-l-admin@midrange.com
[mailto:java400-l-admin@midrange.com]On Behalf Of Xu, Weining
Sent: Thursday, September 20, 2001 6:24 AM
To: 'java400-l@midrange.com'
Subject: RE: How to get the current user ID after sign on to AS400
Thanks, Don,
The getUserId() method could be called for a AS400 object. But in my case,
I have the code like this:
String URL = "jdbc:as400://mysystem/databaseXYZ";
Class.forName("com.ibm.as400.access.AS400JDBCDriver");
con = DriverManager.getConnection(URL);
How do I get the AS400 object here. The AS400 sign on screen was invoked at
the line of code: con = DriverManager.getConnection(URL); After this line
was executed, con has an implicit object as400_ which contains the userId I
just signed on.
So I assume that I should have something like this after con =
DriverManager.getConnection(URL);
String user = aAS400.getUserID();
How could I get this implicit aAS400 object from con? If I create a AS400
object as: AS400 aAS400 = new AS400(); that would not be the same object
(as400_) after the connection.
Any suggestions?
Wayne
-----Original Message-----
From: Donald Whittaker [mailto:donald_whittaker@yahoo.com]
Sent: Wednesday, September 19, 2001 4:16 PM
To: java400-l@midrange.com
Subject: Re: How to get the current user ID after sign on to AS400
The AS400 (connection) object has a .getUserID()
method that returns a String.
URL = "jdbc:as400://mysystem/database" +
myAS400.getUserID();
Hope this helps,
Don Whittaker
--- "Xu, Weining" <Weining.Xu@AIG.com> wrote:
> Hi, all,
>
> I have a program using JDBC driver to access DB2 on
> AS400. I will let the
> different users to use different testing
> databases(libraries) on AS400. So
> after the program connected to AS400, I need to know
> the user ID who just
> signed on AS400 in order to set up a URL as
> "jdbc:as400://mysystem/databaseXYZ". Then use this
> URL to make a
> connection, such as: con =
> DriverManager.getConnection(URL);
>
> Is there anyway I could get the current userID,
> something like:
>
> if (userID.equals("John")){
> URL = "jdbc:as400://mysystem/databaseJohn";
> }
> else if (userID.equals("Tom")){
> URL = "jdbc:as400://mysystem/databaseTom";
> }
>
> con = DriverManager.getConnection(URL);
>
> Thanks for any helps.
>
> Wayne
>
>
>
> _______________________________________________
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> iSeries / AS400 (JAVA400-L) mailing list
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