Re: Struggling with API QDFRTVFD

[Scott Klement <c400-l@xxxxxxxxxxxxxxxx>]

Maybe I'm not understanding, but... wouldn't it simply be like this?

if (QDFFFINF->WDFFFIOA == 0x01) {
  // whatever
}

Since WDFFFIOA isn't a pointer, it's just a byte, can't you just check 
it directly?

Sorry... I haven't following this whole conversation, so I might be 
missing something important.

-SK

On 8/19/2014 8:10 AM, Frank Kolmann wrote:
> Hi Jevgeni
>
>
> The RPG Program I have here does get the hidden field names and attributes.
> For getting the basic stuff it works well.
>   http://wiki.midrange.com/index.php/QDFRTVFD
>
> I am converting it to C but I am stuck on converting this line of code
>
>   if        QDFFFINF.WDFFFIOA = x'01'
>
> I coded it in C as a strncmp but I get this compile error.
> I tried many things to attempt to cast from const char*  to char but I
> am failing.
> (the C code of the program is here
> http://wiki.midrange.com/index.php/CQDFRTVFD
>    It is a mix of the IBM code and the code I am converting , I am using the
> IBM code as a guide to the conversion
>
>   also I must admit I dont really know what this code means
>   p_QDFFINFO = (QDFFINFO_t *)((char *) p_QDFFBASE + p_QDFFBASE->WDFFINOF);
>   I know it sets a pointer to the data but what does
>           (QDFFINFO_t *)((char *)  mean ?
>
>
> This is and example of the compile error I am getting.
>    217
> |
>    218    17 |   if (strncmp(p_QDFFFINF->WDFFFIOA, Attrib, 1) == 0)
> {
>    218    17 +   if ((_STRNCMPNULL((p_QDFFFINF->WDFFFIOA),(Attrib),(1))) ==
> 0) {
> *=SEVERE==========> a - CZM0280  Function argument assignment between types
> "const char*" and "char" is not allowed.
>    219    18 |    NumFlds +=
> 1;
>    220       |    }
>
> However there are other uses of strncmp in the program that compile just
> fine.
> for example.
>
> 253     4 |    for (i=0; i<p_QDFFBASE->WDFFRCS; ++i)
> {
> 254     5 |    if (strncmp(p_QDFARFTE->WDFARFNM,MyRec,10) == 0)
> {
> 255     6 |       RecIndex = i + 1; /* Entry in QDFARFTE table for the
> requested name*/
> 256
>
>
> Thanks Buck for the insight on what to return.
> I think I will just allocate an array in the caller and pass in a pointer
> to the array
> and see how that goes.
>
>
> > date: Mon, 18 Aug 2014 16:07:35 +0300
> > from: Jevgeni Astanovski <jevgeniast@xxxxxxxxx>
> >
> > I used this program as a starting point and successfully retrieved
> > ALMOST everything.
> > I needed the following:
> > Format name, field name, field I/O attribute (Input, Output, Both,
> > Hidden), field type and field length.
> > As wrote earlier my failure was with hidden fields.
> > I found one place where hidden fields names could be retrieved and
> > another place where I could find (probably) these fields necessary
> > attributes - but without field names!
> > Names where available for all but hidden....