Re: Basic c question again - type casting

What you have done is to tell the compiler "Trust me. I am really giving you a char**".

Whether it will work depends on whether you have lied to the compiler.

We probably can't tell you much on this one without seeing more of the code.

C is not the kind of language where your program is likely to work just because it compiled, so good luck and make sure you test it well. ;-)

-Marty

-----Original Message-----
From: Lim Hock-Chai
Sent: Thursday, June 12, 2008 5:41 PM
To: C programming iSeries / AS400
Subject: Re: [C400-L] Basic c question again - type casting


Ok. I think I got it.

I did below and it compile. Not sure if it will run correctly or not.
But at least it compiled :)
logECD_STP((char **) &data);


I was doing this and compiler is not likely it
logECD_STP((char *) &data);

-----Original Message-----
From: c400-l-bounces+lim.hock-chai=usamobility.com@xxxxxxxxxxxx
[mailto:c400-l-bounces+lim.hock-chai=usamobility.com@xxxxxxxxxxxx] On
Behalf Of Lim Hock-Chai
Sent: Thursday, June 12, 2008 4:09 PM
To: C programming iSeries / AS400
Subject: [C400-L] Basic c question again - type casting

If I've a function like below:
void logECD_STP3(const char **dataRcv);


Below compile and work fine:
char * data;
// code that put stuff into data
. . .
logECD_STP(&data);



How do I do the same thing if I've
UAM * data;
// code that put stuff into data
. . .
logECD_STP(&data); <== I got a compile error Function argument
assignment between types "unsigned char* const*" and "struct
uasmgfile**"