The three line example you presented would work, but beware, you only
allocated 20 bytes and you have more than that in your message. C will let
you get yourself into a lot of trouble with simple mistakes like that.
You will need to "manually" allocate a buffer somehow, as you have done, no
little cute shortcuts like your one-line example, like you could do in Java
or other languages.
If you knew your message would always be built from a string and an int, you
could make your function accept those arguments like
Void myFunction(char *message, int myInt)
and then build your message within myFunction, but I don't think that's what
you were looking for.
-Marty
-----Original Message-----
From: Lim Hock-Chai
Sent: Thursday, June 12, 2008 10:59 AM
To: C programming iSeries / AS400
Subject: Re: [C400-L] basic c question about char *
Thank you for all the reply. Now I've a better understanding of char *.
One more question:
Void myFunction(char *message)
myFunction("my static message");
// above function call is pretty straight forward. But what if I need
to pass non static message to it? Is there a way to do it without
having to create a char * or char [] variable. Something like this (I
know the syntax is not correct):
myFunction("my static message" + myInt);
Or do I have to do
char myMessage[20];
sprintf(myMessage, "my non Static message %i", myInt);
myFunction(myMessage);
-----Original Message-----
From: c400-l-bounces+lim.hock-chai=usamobility.com@xxxxxxxxxxxx
[mailto:c400-l-bounces+lim.hock-chai=usamobility.com@xxxxxxxxxxxx] On
Behalf Of Lim Hock-Chai
Sent: Wednesday, June 11, 2008 4:36 PM
To: C programming iSeries / AS400
Subject: [C400-L] basic c question about char *
can somebody help me understand how char * work?
char * s1;
s1 = "assign a value";
s1 = "assign another value"; //does c auto deallocate storage and
reallocate a longer one for this assignment?
. . .
char * s1
int myInt = 10;
sprintf(s1, "test %i", myInt); //why is s1 contains *null after this
assignment?
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