Re: Compiling a SQLCBLLE program

[Jerry Adams <Jerry@xxxxxxxxxxxxxxx>]

That's what I thought but, since I don't program using Cobol, I prompted on the CRTSQLCBLI command.  The only valid options that prompting (F4) and Help (F1) show are *None and *Source.  These are, also, the only options available for the CRTSQLRPGI command.  I tried using *List on one of my SQLRPGLE programs, and it barfed.

Jerry C. Adams
IBM System i Programmer/Analyst
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-----Original Message-----
From: wdsci-l-bounces@xxxxxxxxxxxx [mailto:wdsci-l-bounces@xxxxxxxxxxxx] On Behalf Of Charles Wilt
Sent: Friday, March 26, 2010 12:23 PM
To: Rational Developer for IBM i / Websphere Development Studio Client for System i & iSeries
Subject: Re: [WDSCI-L] Compiling a SQLCBLLE program

You want DBGVIEW(*LIST)...

DBGVIEW(*SOURCE) means debug will display the source from the source
file, it's not included in the object.

However, I think you should be able to right click on the include line
and open the included member in another tab.

HTH,
Charles

On Fri, Mar 26, 2010 at 10:37 AM, Rod Verity <rod_verity@xxxxxxxxxxxxxx> wrote:
> I am attempting to compile an SQLCBLLE program for the first time from RD
> Power(or whatever the accepted name is). ILE is new for us so both ILE and
> RD Power are first time shots.  The job shows the following compile
> command:
>
> Message . . . . :  -CALL PGM(QDEVTOOLS/QRSEEXEC)
>  PARM('/home/IISRV/.eclipse/RSE/SBM00005.log' 'CRTSQLCBLI
>  OBJ(IUTO56A/CSBM9594) SRCFILE(IUTS56A/SRCE) SRCMBR(CSBM9594)
> OPTION(*EVENTF)
>  INCFILE(QLBLSRC) REPLACE(*YES) DBGVIEW(*SOURCE) USRPRF(*OWNER)
>  COMPILEOPT(*SOURCE)')
>
> When I go into debug, the code inside the copybooks doesn't show. Can
> anyone see what parameter I am missing to make that happen? I have tried
> just about all combinations I can think of. The program works but I just
> can't see the contents of the copies.
>
> Thanks for your help,
> Rod
>
>
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