Re: scanr issue?

[Peter Dow <petercdow@xxxxxxxxx>]

I agree.  However, I think you can do what you want with

xx = %scanr(' ':name);

dow xx > 1;
 xx = %scanr(' ':cpname : 1 : xx-1);
enddo;

Since start:length is specifying a substring, just keep limiting the 
substring by changing the length.

Or think of it as the length is now the starting position for %SCANR.

--
*Peter Dow* /
Dow Software Services, Inc.
909 793-9050
petercdow@xxxxxxxxx
pdow@xxxxxxxxxxxxxx /


On 10/20/2022 6:26 AM, eric bothes wrote:
> just seems a bit convoluted.  if scan goes from left to right, scanr 
> should go right to left.
>
> i'm actually looking for the first blank space prior to position 30. i 
> was hoping to do something like this:
>
> xx = %scanr(' ':name);
>
> dow xx > 30
>  xx = %scanr(' ':cpname:xx-1); assuming it would go right to left
> enddo
>
> looks like using for loop downto might be my best option.
>
> On 10/19/2022 8:37 PM, Peter Dow wrote:
> > D source          s            200
> > D pos             s             10  0
> >
> >   source = 'aaaxaaaxaa';
> >   pos = %scanr('x':source);             should return 8
> >   pos = %scanr('x':source:6);          should return 4
> >   *inlr = *on;
> >
> > You can still use %SCANR.  Just specify the substring (start, length) 
> > you want to scan as
> >
> > pos = %scanr('x':source:1:7);
> >
> > Your first %scanr has already scanned positions 8-10.
> >
> >
> > On 10/19/2022 4:10 PM, eric bothes wrote:
> > > hmmm..
> > >
> > > i would have thought it would work like %scan, but in reverse.
> > >
> > > So i guess i would need to do a do loop to find what i am looking for.
> > >
> > > On 10/19/2022 6:58 PM, Peter Dow wrote:
> > > > Hi Eric,
> > > >
> > > > Looks wrong, doesn't it?  The problem is, the "start" position is 
> > > > not what you would expect.  From the v7r3 RPGLE reference manual:
> > > >
> > > > "The start position and length specify the substring of the source 
> > > > string to be searched. The start position
> > > >  defaults to 1 and the length defaults to the remainder of the 
> > > > source string. The result is always the
> > > >  position in the source string even if the starting position is 
> > > > specified."
> > > >
> > > > The start position does NOT specify where %SCANR starts searching. 
> > > > The start plus the length defines the substring to be searched.
> > > >
> > > > In your example,
> > > >
> > > > pos = %scanr('x':source:6);
> > > >
> > > > it scans positions 6 - 10, and finds the 'x' at position 8.
> > > >
> > > > It does NOT start scanning at pos.6 and work backwards.
> > > >
> > > > --
> > > > *Peter Dow* /
> > > > Dow Software Services, Inc.
> > > > 909 793-9050
> > > > petercdow@xxxxxxxxx
> > > > pdow@xxxxxxxxxxxxxx
> > > >
> > > > /
> > > > On 10/19/2022 3:41 PM, eric bothes wrote:
> > > > > i have the following code. They both return 8 rather then 8 and 4 
> > > > > respectively.
> > > > >
> > > > > does anyone else experience this.
> > > > >
> > > > > D source          s            200
> > > > > D pos             s             10  0
> > > > >
> > > > >   source = 'aaaxaaaxaa';
> > > > >   pos = %scanr('x':source);             should return 8
> > > > >   pos = %scanr('x':source:6);          should return 4
> > > > >   *inlr = *on;