Re: Sorta on more than one field

Yes - but ... SORTA can only handle one key in one array at a time.

In the IBM example there were two arrays one nested within the other. That allowed the outer layer to be sorted in manager sequence and then the inner layer to be sorted on name within that.

However had the array been structured like so:

Dcl-ds teams qualified dim(xx);
name varchar(25);
manager varchar(25);
End-ds;

i.e. the manager name and the employee name are pairs.

With this structure SORTA can _either_ sort in name order _or_ in manager order. It cannot sort in name in manager sequence. qsort could - but not SORTA.

On Dec 9, 2019, at 9:08 PM, Booth Martin<booth@xxxxxxxxxxxx> wrote:

Thank you. That helped. I am loading the array wrong.

Now I have to figure out how to load the array.

Then it is possible and relatively easy to sort several fields with SORTA? If the array is properly constructed?


On 12/9/2019 8:44 PM, Jon Paris wrote:

What is confusing you Booth?

There is an outer array of managers. Each of the manager elements consists of the managers name and a DS array of their employees. Each element of that emps array has the persons name.

To sort it employee in manager sequence you must first order the outer elements (manager) and then order the employees within each manager. Hence the nested for loops.

Maybe the structure of the data would be clearer if translated to current dcl capabilities? Like so:


Dcl-ds teams QUALIFIED DIM(2)
manager varchar(25);
Dcl-ds emps Dim(2);
name varchar(25);
End-ds umps;
End-ds teams;

On Dec 9, 2019, at 8:33 PM, Booth Martin<booth@xxxxxxxxxxxx> wrote:

I am trying to follow the instructions but getting helplessly confused.

section from the manual: |SORTA (Sort an Array)<https://www.ibm.com/support/knowledgecenter/en/ssw_ibm_i_72/rzasd/zzsorta.htm>|

"...|||// Sort the TEAMS array first by the MANAGER subfield |

|// and then by the EMPS.NAME subfields *SORTA teams(*).manager; for i = 1 to %ELEM(TEAMS); SORTA teams(i).emps(*).name; endfor;* // After the first sort, by MANAGER: ..." ---------------------------------------------- This says that we can sort fields within fields with a simple loop? |

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(870)576-9371
(802)461-5349

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