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Thank you. That helped.  I am loading the array wrong.

Now I have to figure out how to load the array.

Then it is possible and relatively easy to sort several fields with SORTA?  If the array is properly constructed?


On 12/9/2019 8:44 PM, Jon Paris wrote:
What is confusing you Booth?

There is an outer array of managers. Each of the manager elements consists of the managers name and a DS array of their employees. Each element of that emps array has the persons name.

To sort it employee in manager sequence you must first order the outer elements (manager) and then order the employees within each manager. Hence the nested for loops.

Maybe the structure of the data would be clearer if translated to current dcl capabilities? Like so:


Dcl-ds teams QUALIFIED DIM(2)
manager varchar(25);
Dcl-ds emps Dim(2);
name varchar(25);
End-ds umps;
End-ds teams;



On Dec 9, 2019, at 8:33 PM, Booth Martin <booth@xxxxxxxxxxxx> wrote:

I am trying to follow the instructions but getting helplessly confused.

section from the manual: |SORTA (Sort an Array) <https://www.ibm.com/support/knowledgecenter/en/ssw_ibm_i_72/rzasd/zzsorta.htm>|

"...|||// Sort the TEAMS array first by the MANAGER subfield |

|// and then by the EMPS.NAME subfields *SORTA teams(*).manager; for i = 1 to %ELEM(TEAMS); SORTA teams(i).emps(*).name; endfor;* // After the first sort, by MANAGER: ..." ---------------------------------------------- This says that we can sort fields within fields with a simple loop? |

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Booth Martin
www.martinvt.com
(870)576-9371
(802)461-5349

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