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But they occur at the hardware/microcode level.


Jon Paris

www.partner400.com
www.SystemiDeveloper.com

On May 24, 2019, at 9:21 AM, Raul Jager <raul@xxxxxxxxxx> wrote:

True, but converting binary to char uses one division for each digit...

On 5/23/19 5:56 PM, Jon Paris wrote:
%REM will involve division Raul - which is about the slowest thing any computer can do. I'd be horrified if it was faster than %Int. In fact I'd be surprised if it ran at less than 3x the time.


Jon Paris

www.partner400.com
www.SystemiDeveloper.com

On May 23, 2019, at 5:38 PM, Raul Jager <raul@xxxxxxxxxx> wrote:

Not sure, but %int may cause a conversion to binary (may be slow)

You can use %char(%rem(%dec(ellevenFour: 7: 0): 100)) ;

That will eliminate decimal places, eliminate the first digits if the
number is bigger than 99 and convert to char. If your variable is 11 .
4 it can hold values > 99.

On 5/23/19 4:53 PM, Booth Martin wrote:
%int(). ah, yes. Glad I asked. Knew about %int() yet I didn't
connect the dots. Thank you,

As to the decimal places: The same conversation that "guaranteed"
it'd never be over 99 also assured me there'd never be fractional
quantities, We had > 99 within 72 hours; I am going with truncating
and no leading zeros.

%char(%int()) it shall be then.

Thank you Jon.


On 5/23/2019 9:41 AM, Jon Paris wrote:
twoDigitChar = %Char(%Int(ellevenFour));

Would be one approach. But should the decimals round or just be
truncated? What do you want if the number is (say) 0.1234 - do you
want the zero or blanks? If there is only one significant digit do
you want leading zero or blanks? Or perhaps a single digit number
should be left aligned in the char field.

Can't talk to "best practice" without an adequate spec Booth.


Jon Paris

www.partner400.com
www.SystemiDeveloper.com
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