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  2. RPG400-L
  3. April 2018

Re: Eval *=

On 4/11/2018 10:25 AM, Versfelt, Charles wrote:
Checking a program that bombed, I came across this line of code.
C eval @CurrOptFntSiz *= (1+(@PzFactor*.01))

I don't think I recall seeing *= in an eval statement.
The compiler certainly accepted it.
Is this multiplying @CurrOptFntSize by (1+(@PzFactor*.01)) and setting @CurrOptFntSize equal to that?

For the archives, the '*=' is an assignment operator, which makes it
part of an expression.

IBM i 7.3 > Programming > ILE languages > RPG > ILE RPG Reference >
Operations, Expressions, and Functions > Expressions > Expression Operators

https://www.ibm.com/support/knowledgecenter/ssw_ibm_i_73/rzasd/expropt.htm


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