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Hi, again, Jim:
Perhaps the simplest and most efficient method is to use the underlying
MI assembler instruction TSTBTS (Test Bit in String), which can be
invoked directly in-line in any ILE language, as a "built-in" function.
* TSTBTS returns 0 if bit is "off" and 1 if bit is "on"
D TSTBTS PR 10U 0 extproc( '_TSTBTS' )
D String@ * value
D Offset 10U 0 value
/free
if TSTBTS( %addr( QDBBITS06 ) : 0 ) = 1;
ReUseDlt = *ON;
else;
ReUseDlt = *OFF;
endif;
if TSTBTS( %addr( QDBBITS06 ) : 4 ) = 1;
SQLTable = *ON;
else;
SQLTable = *OFF;
endif;
if TSTBTS( %addr( QDBBITS06 ) : 5 ) = 1;
SQLMQT = *ON;
else;
SQLMQT = *OFF;
endif;
if TSTBTS( %addr( QDBBITS06 ) : 6 ) = 1;
Partitioned = *ON;
else;
Partitioned = *OFF;
endif;
NOTE: TSTBTS can test bits in a field of more than one byte in length;
just use an offset to the desired bit, counting from the left, starting
with 0 as the leftmost bit. Offset must be from 0 to 65535, so the
longest field that can be tested by TSTBTS is 8192 bytes in length.
See:
http://publib.boulder.ibm.com/iseries/v5r1/ic2924/tstudio/tech_ref/mi/TSTBTS.htm
for additional details.
Hope that helps,
Mark S. Waterbury
> On 7/8/2015 2:59 PM, Jim Franz wrote:
Mark - the explanation from Brian is what makes sense. Thanks for the link.
And now I see Vern's example.
The problem (to me) for all the web example found (before) and the IBM ILE
RPG Reference Manual is there is an assumption you wanted to test "all on",
"all off", and "some on".
but I need each value for bits 1, 5, 6, 7 (and they are each individual
values)
Was trying to use /free
Thanks (to all) for the help
Jim
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