RE: Use Of %SubArr

Is Arr defined as an array of 1 byte elements? Did I miss that in the OP?

If so, this could be done:

X = 11;
For i = 1 to %len( WkValue );
Arr(x) = %subst( WkValue: i: 1 );
X += 1;
EndFor;

-Kurt

-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Gqcy
Sent: Tuesday, June 26, 2012 8:53 AM
To: rpg400-l@xxxxxxxxxxxx
Subject: Re: Use Of %SubArr

Kurt,
when I try this I wind up with:
Arr =
' U '


On 6/26/2012 8:42 AM, Anderson, Kurt wrote:

What you want, I believe, is:
Arr(Position) = WkValue;

This is the same as
Eval Arr(Position) = WkValue;

You can even try this in fixed format with Eval as the opcode.

-Kurt

-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx
[mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Robert Munday
Sent: Tuesday, June 26, 2012 8:16 AM
To: RPG400
Subject: Use Of %SubArr

Greetings from the sunny south.


One of my fellow programmers is trying to move a character field to the interior of an array. This is being attempted in /Free and is not generating the correct result.

In fixed format, this is the expression which works (as it always has):


Position = 11

WkValue = 'UN2367, '

MoveA WkValue Arr(Position)

It yields the desired result: ' UN2367, '


This does not work:

WkLength = 8

%SubArr(Array: Position: WkLength) = WkValue

It yields: ' UUUUUUUU '


The array is receiving only the first character of the character field `UN2367`. What is causing this to occur and how can it be fixed to obtain the correct result?


Thanks,



Robert Munday
Munday Software Consultants
Montgomery, AL


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