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Thanks for the reply, but I don't think that this logic would work for the following scenario
1 line A
2
3 line B
4
5 line X
6 line E
The 6th occurrence would remain , when the end result that is wanted is
1 line A
2 line B
3 line X
4 line E

Alan Shore
Programmer/Analyst, Direct Response
E:AShore@xxxxxxxx
P:(631) 200-5019
C:(631) 880-8640
"If you're going through Hell, keep going" - Winston Churchill


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Morgan, Paul
Sent: Wednesday, April 27, 2011 4:27 PM
To: RPG programming on the IBM i / System i
Subject: RE: Filling an array from the first occurrence on down

How about:

For X = %Elem( Line ) - 1 downto 1;
If Line( X ) = *Blanks;
%SubArr( Line : X ) = %SubArr( Line : X + 1 );
EndIf;
EndFor;

Paul Morgan

Principal Programmer Analyst
IT Supply Chain/Replenishment


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Alan Shore
Sent: Tuesday, April 26, 2011 2:21 PM
To: 'rpg400-l@xxxxxxxxxxxx'
Subject: Filling an array from the first occurrence on down

Hi everyone
I'm having one of those days where no matter what I do, I just cannot get my head around what should be a simple problem Hopefully someone is kind enough to provide an answer I have an array
D LINE S 30 DIM(6)

Data can be in any combination of the occurrences (or none at all) I need to create logic so that data is moved down to fill in from the first, through the second, then third etc., until the only blanks are in the trailing occurrences

Hopefully I explained it correctly, here is an example
1
2 data 1
3
4
5 data here
6 f=data 2

Becomes
1 data 1
2 data here
3 f=data 2
4
5
6
NOTE - I don't want the information sorted, just moved up As always, any and all responses gratefully appreciated

Alan Shore
Programmer/Analyst, Direct Response
E:AShore@xxxxxxxx
P:(631) 200-5019
C:(631) 880-8640
"If you're going through Hell, keep going" - Winston Churchill

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