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Hi Ron

As others have said, it's because "user" is a debug keyword - so you have to use the %var() function there to have debug treat it as a variable. I've never used a variable named "user", so never have had to use that function in debug.

Vern

On 7/6/2010 2:42 PM, Ronald Newman wrote:
If you run this code you can see that USER will contain the users name. However when in debug and you use F11 to display the contents of USER is when you get the syntax error. It may be the INZ(*user) that is causing the problem in debug


1 D userid s 10a inz(*user) 2 D user s 10a 3 c move userid user 4 c user dsply user 5 c eval *inlr = *on
Ron Newman








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