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For a straight-forward SELECT yes, but if you needed/wanted to use a
dynamic SELECT, it would be nice.
Perfect example would be I'm building a SELECT statement based on Filters,
that will construct me a
WHERE clause dynamically, and I wanted to see the record count of that
filter.

dav


David L. Mosley, Jr.
Technical Solutions Architect
Dancik International, Ltd.
2000 CentreGreen Way, Suite 250
Cary, NC 27513

www.dancik.com



Charles Wilt <charles.wilt@xxxxxxxxx>
Sent by: rpg400-l-bounces@xxxxxxxxxxxx
05/25/2010 10:52 AM
Please respond to
RPG programming on the IBM i / System i <rpg400-l@xxxxxxxxxxxx>


To
"RPG programming on the IBM i / System i" <rpg400-l@xxxxxxxxxxxx>
cc

Subject
Re: Quick SQL expression evaluation






You don't need to use dynamic SQL for COUNT(*)

exec sql
select count(*) into :myResult
from item;

Works fine.

Charles

On Tue, May 25, 2010 at 10:10 AM, <dmosley@xxxxxxxxxx> wrote:
That's an interesting trick. I would have hoped that some like using
"SELECT COUNT(*) INTO ? FROM ITEM" would work the same.

/Free
String = 'SELECT COUNT(*) INTO ? FROM ITEM';
/Exec SQL Prepare DynSQL From :String;
/Exec SQL Execute DynSQL using :MyResult;
Dsply MyResult;
/End-Free


David L. Mosley, Jr.
Technical Solutions Architect
Dancik International, Ltd.
2000 CentreGreen Way, Suite 250
Cary, NC 27513

www.dancik.com



Luis Rodriguez <luisro58@xxxxxxxxx>
Sent by: rpg400-l-bounces@xxxxxxxxxxxx
05/25/2010 05:04 AM
Please respond to
RPG programming on the IBM i / System i <rpg400-l@xxxxxxxxxxxx>


To
"RPG programming on the IBM i / System i" <rpg400-l@xxxxxxxxxxxx>
cc

Subject
Re: Quick SQL expression evaluation






Wow!! Thanks Birgitta!! ..

One can always trust that you will find the solution to almost any SQL
problem, this one will go into the archives.


Best Regards,

Luis Rodriguez
IBM Certified Systems Expert â eServer i5 iSeries


On Tue, May 25, 2010 at 8:21 AM, Birgitta Hauser
<Hauser@xxxxxxxxxxxxxxx>wrote:

Try the following:

D MyResult S 11P 2
D String S 256A Varying
D Expr S 256A Varying inz('2 + 2')
/Free
String = 'Values(' + Expr + ') into ?';
/Exec SQL Prepare DynSQL From :String;
/Exec SQL Execute DynSQL using :MyResult;
Dsply MyResult;
/End-Free




Mit freundlichen GrÃÃen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars."
(Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training
them
and keeping them!"

-----UrsprÃngliche Nachricht-----
Von: rpg400-l-bounces@xxxxxxxxxxxx
[mailto:rpg400-l-bounces@xxxxxxxxxxxx]
Im
Auftrag von Dennis Lovelady
Gesendet: Tuesday, 25. May 2010 14:30
An: 'RPG programming on the IBM i / System i'
Betreff: Quick SQL expression evaluation

I am trying to write a procedure I thought would be extremely simple: a
short SQL evaluation program that would simply take an expression and
return
the result of SQL operating on that expression. For a silly example:

Exec sql set :myResult = 2 + 2 ;



To minimize complexity, I am passing the '2 + 2' part as a string, so
that
the meat of this very short procedure is:

Exec sql setl :myResult = :myExpression ;



But (and, yes, I know I should have expected this) SQL is seeing it as
the
string "2 + 2" rather than a pair of values with an operator between
them.
Is there an SQL verb/clause that informs the SQL processor that the
following is an expression rather than a string (such as with unix'
"expr"
command)? Or is this just a pipe dream, not worth the effort?



Dennis E. Lovelady
AIM/Skype: delovelady MSN: fastcounter@xxxxxxxxxxxx
<http://www.linkedin.com/in/dennislovelady>
www.linkedin.com/in/dennislovelady --
You can't have everything. Where would you put it?



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