|
/Free
String = 'SELECT COUNT(*) INTO ? FROM ITEM';
/Exec SQL Prepare DynSQL From :String;
/Exec SQL Execute DynSQL using :MyResult;
Dsply MyResult;
/End-Free
Try the following:(Les
D MyResult S 11P 2
D String S 256A Varying
D Expr S 256A Varying inz('2 + 2')
/Free
String = 'Values(' + Expr + ') into ?';
/Exec SQL Prepare DynSQL From :String;
/Exec SQL Execute DynSQL using :MyResult;
Dsply MyResult;
/End-Free
Mit freundlichen GrÃÃen / Best regards
Birgitta Hauser
"Shoot for the moon, even if you miss, you'll land among the stars."
Brown)them
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training
and keeping them!"[mailto:rpg400-l-bounces@xxxxxxxxxxxx]
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Von: rpg400-l-bounces@xxxxxxxxxxxx
Imthat
Auftrag von Dennis Lovelady
Gesendet: Tuesday, 25. May 2010 14:30
An: 'RPG programming on the IBM i / System i'
Betreff: Quick SQL expression evaluation
I am trying to write a procedure I thought would be extremely simple: a
short SQL evaluation program that would simply take an expression and
return
the result of SQL operating on that expression. For a silly example:
Exec sql set :myResult = 2 + 2 ;
To minimize complexity, I am passing the '2 + 2' part as a string, so
the meat of this very short procedure is:the
Exec sql setl :myResult = :myExpression ;
But (and, yes, I know I should have expected this) SQL is seeing it as
string "2 + 2" rather than a pair of values with an operator betweenthem.
Is there an SQL verb/clause that informs the SQL processor that the"expr"
following is an expression rather than a string (such as with unix'
command)? Or is this just a pipe dream, not worth the effort?list
Dennis E. Lovelady
AIM/Skype: delovelady MSN: fastcounter@xxxxxxxxxxxx
<http://www.linkedin.com/in/dennislovelady>
www.linkedin.com/in/dennislovelady --
You can't have everything. Where would you put it?
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